题目内容
(请给出正确答案)
[不定项选择题]
某钢尺的尺长方程式为:L=30-0.003+1.25×10-5×30×(t-20℃),若用其在4℃的温度下丈量了60m,则其温度改正数和实际长度分别为()。
A.-0.012m;59.988m
B.+0.012m;60.012m
C.-0.012m;59.982m
D.+0.012m;59.982m
暂无答案
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A.-0.012m;59.988m
B.+0.012m;60.012m
C.-0.012m;59.982m
D.+0.012m;59.982m